from collections import Counter# 列表l_one = [1709020621, 1709020621, 1770603107, 1770603105, 1770603106, 1770603105, 1709020621]# 把列表换成字典统计c = Counter(l_one)print(c)k = c.most_common(len(c))  # 找出全部元素从大到小的元素频率以及对应的次数。# 转化成列表形式，列表每一项又是元祖。print(k)# 数据按照从大到小的顺序输出for i in k:    print(str(i[0]) + " " + str(i[1]))